2x + 3y = 12 and 2x − y = 4
Today we'll solve a system of two equations using elimination. Our goal: find the x and y that make BOTH equations true.
Here are our two equations. Notice both have 2x — that's our chance to eliminate x.
Look! The x-terms match: 2x in the top, 2x in the bottom. If we subtract, the x's will cancel.
Let's subtract the bottom equation from the top equation, term by term.
Two x minus two x equals zero. The x is eliminated!
Three y minus negative y is three y plus y, which is four y.
Twelve minus four is eight. So four y equals eight.
Divide both sides by four. y equals two.
Now plug y equals two back into the first equation: 2x plus 3 times 2 equals 12.
Three times two is six, so 2x plus six equals twelve.
Subtract six from both sides, then divide by two. x equals three.
The solution is x equals three, y equals two. One point makes both equations true!